1=ln(2x^2)

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Solution for 1=ln(2x^2) equation:


Simplifying
1 = ln(2x2)

Remove parenthesis around (2x2)
1 = ln * 2x2

Reorder the terms for easier multiplication:
1 = 2ln * x2

Multiply ln * x2
1 = 2lnx2

Solving
1 = 2lnx2

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '-2lnx2' to each side of the equation.
1 + -2lnx2 = 2lnx2 + -2lnx2

Combine like terms: 2lnx2 + -2lnx2 = 0
1 + -2lnx2 = 0

Add '-1' to each side of the equation.
1 + -1 + -2lnx2 = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -2lnx2 = 0 + -1
-2lnx2 = 0 + -1

Combine like terms: 0 + -1 = -1
-2lnx2 = -1

Divide each side by '-2nx2'.
l = 0.5n-1x-2

Simplifying
l = 0.5n-1x-2

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